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Subjects
Class 10MathematicsPolynomialsPolynomials in one variableMediumLevel 46
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What is the value of (p(0)+p(1)) for (p(x)=2x^3-5x^2+7x-4)?

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Answer and explanation

Correct answer: (0)

(p(0)=-4) and (p(1)=2-5+7-4=0), so (p(0)+p(1)=-4). Always substitute each value separately before adding.

Related tags

EvaluationSubstitutionPolynomial

Frequently asked questions

What is the correct answer to this question?

(0)

Why is this the correct answer?

(p(0)=-4) and (p(1)=2-5+7-4=0), so (p(0)+p(1)=-4). Always substitute each value separately before adding.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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10 more MCQs
  1. 1If (p(x)=x^2-8x+10), what are its zeroes?
  2. 2Which option is the simplified form of (x^8 - 81) / (x^4 - 9), where x^4 ≠ 9?
  3. 3Which expression is a polynomial in one variable (x)?
  4. 4What is the degree of the polynomial p(x) = 4x^3 − 2x + 9?
  5. 5What is the constant term of the polynomial \(7x^2+5x-11\)?
  6. 6What is the coefficient of x^2 in 5x^4 − 3x^2 + x − 6?
  7. 7Which polynomial is a quadratic polynomial?
  8. 8Which expression is not a polynomial?
  9. 9For the polynomial \(p(x)=2x^2-3x+1\), what is the value of \(p(1)\)?
  10. 10How many terms are there in q(x) = x^3 + 2x^2 − x + 4?
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