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What is the value of \(\left(\frac{27}{8}\right)^{-\frac{2}{3}}\)?\(\left(\frac{27}{8}\right)^{-\frac{2}{3}}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{4}{9}\)\(\frac{4}{9}\)
Since \(\left(\frac{27}{8}\right)^{\frac{1}{3}}=\frac{3}{2}\), \(\left(\frac{27}{8}\right)^{-\frac{2}{3}}=\left(\frac{3}{2}\right)^{-2}=\frac{4}{9}\). In exams, take the cube root first.\(\left(\frac{27}{8}\right)^{\frac{1}{3}}=\frac{3}{2}\), इसलिए \(\left(\frac{27}{8}\right)^{-\frac{2}{3}}=\left(\frac{3}{2}\right)^{-2}=\frac{4}{9}\)। परीक्षा में पहले घनमूल निकालें।
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