(\left\(\frac{27}{8}\right\)^{-\frac{2}{3}}) का मान क्या है?
What is the value of (\left\(\frac{27}{8}\right\)^{-\frac{2}{3}})?
Explanation opens after your attempt
A. \(\frac{4}{9}\)
Concept
Since (\left\(\frac{27}{8}\right\)^{\frac{1}{3}}=\frac{3}{2}), (\left\(\frac{27}{8}\right\)^{-\frac{2}{3}}=\left\(\frac{3}{2}\right\)^{-2}=\frac{4}{9}). In exams, take the cube root first.
Why this answer is correct
The correct answer is A. \(\frac{4}{9}\). Since (\left\(\frac{27}{8}\right\)^{\frac{1}{3}}=\frac{3}{2}), (\left\(\frac{27}{8}\right\)^{-\frac{2}{3}}=\left\(\frac{3}{2}\right\)^{-2}=\frac{4}{9}). In exams, take the cube root first.
Exam Tip
(\left\(\frac{27}{8}\right\)^{\frac{1}{3}}=\frac{3}{2}), इसलिए (\left\(\frac{27}{8}\right\)^{-\frac{2}{3}}=\left\(\frac{3}{2}\right\)^{-2}=\frac{4}{9})। परीक्षा में पहले घनमूल निकालें।
Login to save your score, XP, coins and progress.
