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What is the value of \(\left(\dfrac{81}{16}\right)^{-\frac{1}{2}}\)?\(\left(\dfrac{81}{16}\right)^{-\frac{1}{2}}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (,\dfrac{4}{9},)(,\dfrac{4}{9},)
First, \(\left(\dfrac{81}{16}\right)^{\frac{1}{2}}=\dfrac{9}{4}\), then the negative exponent gives (\dfrac{4}{9}). In exams, check both the square root and the reciprocal.पहले \(\left(\dfrac{81}{16}\right)^{\frac{1}{2}}=\dfrac{9}{4}\), फिर ऋणात्मक घात से उत्तर (\dfrac{4}{9}) होता है। परीक्षा में square root और reciprocal दोनों देखें।
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