What is the value of (\frac{\sqrt{147}-2\sqrt{12}+3\sqrt{27}}{\sqrt{3}})?(\frac{\sqrt{147}-2\sqrt{12}+3\sqrt{27}}{\sqrt{3}}) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (16)(16)
Here (\sqrt{147}=7\sqrt{3}), (2\sqrt{12}=4\sqrt{3}), and (3\sqrt{27}=9\sqrt{3}), so the numerator is (12\sqrt{3}). Therefore, the value should be (12).(\sqrt{147}=7\sqrt{3}), (2\sqrt{12}=4\sqrt{3}), और (3\sqrt{27}=9\sqrt{3}), इसलिए अंश (12\sqrt{3}) नहीं बल्कि (7\sqrt{3}-4\sqrt{3}+9\sqrt{3}=12\sqrt{3}) है। अतः मान (12) होना चाहिए।
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