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What is the value of 8\frac{16^2}{2^5}9?

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Answer and explanation

Correct answer: 8

Since \(16=2^4\), we get \(16^2=(2^4)^2=2^8\). Therefore, \(\frac{16^2}{2^5}=\frac{2^8}{2^5}=2^{8-5}=2^3=8\). Exam tip: when dividing powers with the same base, subtract their exponents.

Related tags

PolynomialsReal NumbersExponentsPowers Of TwoExponent Laws

Frequently asked questions

What is the correct answer to this question?

8

Why is this the correct answer?

Since \(16=2^4\), we get \(16^2=(2^4)^2=2^8\). Therefore, \(\frac{16^2}{2^5}=\frac{2^8}{2^5}=2^{8-5}=2^3=8\). Exam tip: when dividing powers with the same base, subtract their exponents.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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