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What is the simplified value of (\frac{(2^{5})^{3}\cdot(4^{-2})}{8^{2}})?(\frac{(2^{5})^{3}\cdot(4^{-2})}{8^{2}}) का सरल मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (2^{5})(2^{5})
Here ((2^{5})^{3}=2^{15}), (4^{-2}=2^{-4}), and (8^{2}=2^{6}), so the net exponent is (15-4-6=5). In exams, convert all bases to (2).((2^{5})^{3}=2^{15}), (4^{-2}=2^{-4}), और (8^{2}=2^{6}), इसलिए कुल घात (15-4-6=5) है। परीक्षा में सभी आधार (2) में बदलें।
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