\(\sqrt{20}+\sqrt{45}+\sqrt{125}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{20}+\sqrt{45}+\sqrt{125}\)?

Explanation opens after your attempt
Correct Answer

A. \(10\sqrt{5}\)

Step 1

Concept

\(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{125}=5\sqrt{5}\).

Step 2

Why this answer is correct

The sum is \(2\sqrt{5}+3\sqrt{5}+5\sqrt{5}=10\sqrt{5}\).

Step 3

Exam Tip

Once radicals are like terms, add only the coefficients. चरण 1: \(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), और \(\sqrt{125}=5\sqrt{5}\)। चरण 2: योग \(2\sqrt{5}+3\sqrt{5}+5\sqrt{5}=10\sqrt{5}\) है। चरण 3: समान वर्गमूल बनने पर केवल गुणांक जोड़ें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(\sqrt{20}+\sqrt{45}+\sqrt{125}\) का सरल रूप क्या है? / What is the simplified form of \(\sqrt{20}+\sqrt{45}+\sqrt{125}\)?

Correct Answer: A. \(10\sqrt{5}\). Explanation: चरण 1: \(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), और \(\sqrt{125}=5\sqrt{5}\)। चरण 2: योग \(2\sqrt{5}+3\sqrt{5}+5\sqrt{5}=10\sqrt{5}\) है। चरण 3: समान वर्गमूल बनने पर केवल गुणांक जोड़ें। / Step 1: \(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{125}=5\sqrt{5}\). Step 2: The sum is \(2\sqrt{5}+3\sqrt{5}+5\sqrt{5}=10\sqrt{5}\). Step 3: Once radicals are like terms, add only the coefficients.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{125}=5\sqrt{5}\).

What exam hint can help solve this Mathematics question?

Once radicals are like terms, add only the coefficients. चरण 1: \(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), और \(\sqrt{125}=5\sqrt{5}\)। चरण 2: योग \(2\sqrt{5}+3\sqrt{5}+5\sqrt{5}=10\sqrt{5}\) है। चरण 3: समान वर्गमूल बनने पर केवल गुणांक जोड़ें।