(\left\(\frac{x^{-2}y^{3}}{x^{4}y^{-1}}\right\)^{-1}) का सरल रूप क्या है?
What is the simplified form of (\left\(\frac{x^{-2}y^{3}}{x^{4}y^{-1}}\right\)^{-1})?
Explanation opens after your attempt
A. \(x^{6}y^{-4}\)
Concept
Inside, \(\frac{x^{-2}y^{3}}{x^{4}y^{-1}}=x^{-6}y^{4}\), and raising to (-1) gives \(x^{6}y^{-4}\). In exams, subtract exponents during division.
Why this answer is correct
The correct answer is A. \(x^{6}y^{-4}\). Inside, \(\frac{x^{-2}y^{3}}{x^{4}y^{-1}}=x^{-6}y^{4}\), and raising to (-1) gives \(x^{6}y^{-4}\). In exams, subtract exponents during division.
Exam Tip
अंदर \(\frac{x^{-2}y^{3}}{x^{4}y^{-1}}=x^{-6}y^{4}\), और (-1) घात लेने पर \(x^{6}y^{-4}\) मिलता है। परीक्षा में भाग में घात घटती है।
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