(\left\(\frac{a^{3}b^{-2}}{a^{-1}b^{2}}\right\)^{2}) का सरल रूप क्या है?
What is the simplified form of (\left\(\frac{a^{3}b^{-2}}{a^{-1}b^{2}}\right\)^{2})?
Explanation opens after your attempt
A. \(a^{8}b^{-8}\)
Concept
Inside, \(a^{3-(-1)}b^{-2-2}=a^{4}b^{-4}\), and squaring gives \(a^{8}b^{-8}\). In exams, watch the sign when subtracting negative exponents.
Why this answer is correct
The correct answer is A. \(a^{8}b^{-8}\). Inside, \(a^{3-(-1)}b^{-2-2}=a^{4}b^{-4}\), and squaring gives \(a^{8}b^{-8}\). In exams, watch the sign when subtracting negative exponents.
Exam Tip
अंदर \(a^{3-(-1)}b^{-2-2}=a^{4}b^{-4}\), इसलिए वर्ग करने पर \(a^{8}b^{-8}\) है। परीक्षा में ऋणात्मक घात घटाते समय चिह्न पर ध्यान दें।
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