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What is the simplified form of \(\left(\frac{3x^{-2}}{y^{-1}}\right)^{3}\cdot\frac{y^{2}}{27}\)?\(\left(\frac{3x^{-2}}{y^{-1}}\right)^{3}\cdot\frac{y^{2}}{27}\) का सरल रूप क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(x^{-6}y^{5}\)\(x^{-6}y^{5}\)
\(\frac{3x^{-2}}{y^{-1}}=3x^{-2}y\), its cube is \(27x^{-6}y^{3}\), and multiplying by \(\frac{y^{2}}{27}\) gives \(x^{-6}y^{5}\). In exams, turn division by a negative power into multiplication.\(\frac{3x^{-2}}{y^{-1}}=3x^{-2}y\), इसका घन \(27x^{-6}y^{3}\) है, फिर \(\frac{y^{2}}{27}\) से गुणा करने पर \(x^{-6}y^{5}\) मिलता है। परीक्षा में भाग को ऋणात्मक घात से गुणा में बदलें।
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