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What is the simplified form of \(\left(81x^{4}\right)^{\frac{1}{2}}\), where \(x\ge0\)?\(\left(81x^{4}\right)^{\frac{1}{2}}\) का सरल रूप क्या है, जहाँ \(x\ge0\)?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(9x^{2}\)\(9x^{2}\)
\(\left(81x^{4}\right)^{\frac{1}{2}}=\sqrt{81x^{4}}=9x^{2}\). In exams, the exponent becomes half under a square root.\(\left(81x^{4}\right)^{\frac{1}{2}}=\sqrt{81x^{4}}=9x^{2}\)। परीक्षा में वर्गमूल में घात आधी हो जाती है।
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