\(\frac{1}{2-\sqrt{3}}\) का परिमेय हर वाला रूप क्या है?

What is the rationalized form of \(\frac{1}{2-\sqrt{3}}\)?

Explanation opens after your attempt
Correct Answer

A. \(2+\sqrt{3}\)

Step 1

Concept

To rationalize, \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\). In exams, multiply by the conjugate.

Step 2

Why this answer is correct

The correct answer is A. \(2+\sqrt{3}\). To rationalize, \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\). In exams, multiply by the conjugate.

Step 3

Exam Tip

हर को परिमेय बनाने के लिए \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\)। परीक्षा में संयुग्म से गुणा करें।

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\(\frac{1}{2-\sqrt{3}}\) का परिमेय हर वाला रूप क्या है? / What is the rationalized form of \(\frac{1}{2-\sqrt{3}}\)?

Correct Answer: A. \(2+\sqrt{3}\). Explanation: हर को परिमेय बनाने के लिए \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\)। परीक्षा में संयुग्म से गुणा करें। / To rationalize, \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\). In exams, multiply by the conjugate.

Which concept should I revise for this Mathematics MCQ?

To rationalize, \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\). In exams, multiply by the conjugate.

What exam hint can help solve this Mathematics question?

हर को परिमेय बनाने के लिए \(\frac{1}{2-\sqrt{3}}\cdot\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{2+\sqrt{3}}{4-3}=2+\sqrt{3}\)। परीक्षा में संयुग्म से गुणा करें।