\(\frac{1}{3+\sqrt{8}}\) का परिमेय हर वाला रूप क्या है?

What is the form of \(\frac{1}{3+\sqrt{8}}\) with a rational denominator?

Explanation opens after your attempt
Correct Answer

A. \(3-\sqrt{8}\)

Step 1

Concept

The conjugate of \(3+\sqrt{8}\) is \(3-\sqrt{8}\).

Step 2

Why this answer is correct

\(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\).

Step 3

Exam Tip

Use the conjugate of the denominator for rationalisation. चरण 1: हर \(3+\sqrt{8}\) का संयुग्म \(3-\sqrt{8}\) है। चरण 2: \(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\)। चरण 3: परिमेयकरण में हर का संयुग्म प्रयोग करें।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{3+\sqrt{8}}\) का परिमेय हर वाला रूप क्या है? / What is the form of \(\frac{1}{3+\sqrt{8}}\) with a rational denominator?

Correct Answer: A. \(3-\sqrt{8}\). Explanation: चरण 1: हर \(3+\sqrt{8}\) का संयुग्म \(3-\sqrt{8}\) है। चरण 2: \(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\)। चरण 3: परिमेयकरण में हर का संयुग्म प्रयोग करें। / Step 1: The conjugate of \(3+\sqrt{8}\) is \(3-\sqrt{8}\). Step 2: \(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\). Step 3: Use the conjugate of the denominator for rationalisation.

Which concept should I revise for this Mathematics MCQ?

The conjugate of \(3+\sqrt{8}\) is \(3-\sqrt{8}\).

What exam hint can help solve this Mathematics question?

Use the conjugate of the denominator for rationalisation. चरण 1: हर \(3+\sqrt{8}\) का संयुग्म \(3-\sqrt{8}\) है। चरण 2: \(\frac{1}{3+\sqrt{8}}\times\frac{3-\sqrt{8}}{3-\sqrt{8}}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\)। चरण 3: परिमेयकरण में हर का संयुग्म प्रयोग करें।