\(\frac{1}{2+\sqrt{3}}\) का परिमेय हर वाला रूप क्या है?

What is the form of \(\frac{1}{2+\sqrt{3}}\) with a rational denominator?

Explanation opens after your attempt
Correct Answer

A. \(2-\sqrt{3}\)

Step 1

Concept

The conjugate of the denominator is \(2-\sqrt{3}\).

Step 2

Why this answer is correct

\(\frac{1}{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}}=\frac{2-\sqrt{3}}{4-3}=2-\sqrt{3}\).

Step 3

Exam Tip

For rationalisation, multiply by the conjugate. चरण 1: हर का संयुग्म \(2-\sqrt{3}\) है। चरण 2: \(\frac{1}{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}}=\frac{2-\sqrt{3}}{4-3}=2-\sqrt{3}\)। चरण 3: परिमेयकरण में संयुग्म से गुणा करें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{1}{2+\sqrt{3}}\) का परिमेय हर वाला रूप क्या है? / What is the form of \(\frac{1}{2+\sqrt{3}}\) with a rational denominator?

Correct Answer: A. \(2-\sqrt{3}\). Explanation: चरण 1: हर का संयुग्म \(2-\sqrt{3}\) है। चरण 2: \(\frac{1}{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}}=\frac{2-\sqrt{3}}{4-3}=2-\sqrt{3}\)। चरण 3: परिमेयकरण में संयुग्म से गुणा करें। / Step 1: The conjugate of the denominator is \(2-\sqrt{3}\). Step 2: \(\frac{1}{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}}=\frac{2-\sqrt{3}}{4-3}=2-\sqrt{3}\). Step 3: For rationalisation, multiply by the conjugate.

Which concept should I revise for this Mathematics MCQ?

The conjugate of the denominator is \(2-\sqrt{3}\).

What exam hint can help solve this Mathematics question?

For rationalisation, multiply by the conjugate. चरण 1: हर का संयुग्म \(2-\sqrt{3}\) है। चरण 2: \(\frac{1}{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}}=\frac{2-\sqrt{3}}{4-3}=2-\sqrt{3}\)। चरण 3: परिमेयकरण में संयुग्म से गुणा करें।