What is the factorized form of \(49x^2-64\)?
Answer and explanation
Correct answer: \((7x-8)(7x+8)\)
\(49x^2-64=(7x)^2-8^2\). Using the difference of squares identity \(a^2-b^2=(a-b)(a+b)\), we get \((7x-8)(7x+8)\). Option B does not expand to the given expression, while C and D are squares rather than the correct difference-of-squares factorization. Exam tip: first rewrite both terms as perfect squares.
Frequently asked questions
What is the correct answer to this question?
\((7x-8)(7x+8)\)
Why is this the correct answer?
\(49x^2-64=(7x)^2-8^2\). Using the difference of squares identity \(a^2-b^2=(a-b)(a+b)\), we get \((7x-8)(7x+8)\). Option B does not expand to the given expression, while C and D are squares rather than the correct difference-of-squares factorization. Exam tip: first rewrite both terms as perfect squares.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
