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What are the solutions of (\frac{1}{x}+x=\frac{37}{6}), (x\neq0)?
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Answer and explanation
Correct answer: (x=6,\frac{1}{6})
(6x^2-37x+6=(6x-1)(x-6)), so (x=\frac{1}{6}) and (6). In exams, check whether obtained roots are valid in the original equation.
Frequently asked questions
What is the correct answer to this question?
(x=6,\frac{1}{6})
Why is this the correct answer?
(6x^2-37x+6=(6x-1)(x-6)), so (x=\frac{1}{6}) and (6). In exams, check whether obtained roots are valid in the original equation.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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