\(8x^2-2x-3=0\) के मूल क्या हैं?
What are the roots of \(8x^2-2x-3=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{3}{4},-\frac{1}{2}\)
Concept
(8x-2-2x-3=(4x-3)(2x+1)), so the roots are \(\frac{3}{4}\) and \(-\frac{1}{2}\). In exams, solve both linear factors carefully.
Why this answer is correct
The correct answer is A. \(x=\frac{3}{4},-\frac{1}{2}\). (8x-2-2x-3=(4x-3)(2x+1)), so the roots are \(\frac{3}{4}\) and \(-\frac{1}{2}\). In exams, solve both linear factors carefully.
Exam Tip
(8x-2-2x-3=(4x-3)(2x+1)), इसलिए मूल \(\frac{3}{4}\) और \(-\frac{1}{2}\) हैं। परीक्षा में दोनों रैखिक गुणनखंड सावधानी से हल करें।
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