\(4x^2-12x-7=0\) के मूल क्या हैं?
What are the roots of \(4x^2-12x-7=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{7}{2},-\frac{1}{2}\)
Concept
((2x+1)(2x-7)=0), so \(x=-\frac{1}{2}\) and \(\frac{7}{2}\). In exams, change signs while writing roots.
Why this answer is correct
The correct answer is A. \(x=\frac{7}{2},-\frac{1}{2}\). ((2x+1)(2x-7)=0), so \(x=-\frac{1}{2}\) and \(\frac{7}{2}\). In exams, change signs while writing roots.
Exam Tip
((2x+1)(2x-7)=0), इसलिए \(x=-\frac{1}{2}\) और \(\frac{7}{2}\) हैं। परीक्षा में संकेत बदलकर मूल लिखें।
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