Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

The price of an adult ticket is (x) and a child ticket is (y). If (2x+3y=310) and (3x+2y=340), what is the adult ticket price?

Advertisement

Answer and explanation

Correct answer: ₹80

Using elimination, multiply the first equation by 3 and the second equation by 2: (6x+9y=930) and (6x+4y=680). Subtracting gives (5y=250), so (y=50). Substituting this into (3x+2y=340) gives (3x+100=340), hence (x=80). Therefore, the correct answer is ₹80. A value such as ₹70 does not satisfy both equations together. Exam tip: In elimination, first make the coefficients of one variable equal and then subtract the equations.

Related tags

Pair Of Linear EquationsElimination MethodSubstitution MethodTicket PriceWord ProblemClass 10 Mathematics

Frequently asked questions

What is the correct answer to this question?

₹80

Why is this the correct answer?

Using elimination, multiply the first equation by 3 and the second equation by 2: (6x+9y=930) and (6x+4y=680). Subtracting gives (5y=250), so (y=50). Substituting this into (3x+2y=340) gives (3x+100=340), hence (x=80). Therefore, the correct answer is ₹80. A value such as ₹70 does not satisfy both equations together. Exam tip: In elimination, first make the coefficients of one variable equal and then subtract the equations.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Pair of Linear Equations in Two Variables. Topic: Algebraic methods: Substitution method and Elimination method..

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement