संख्या रेखा पर \( \sqrt{\frac{25}{16}} \) किस बिंदु के बराबर है?

On the number line, \( \sqrt{\frac{25}{16}} \) is equal to which point?

Explanation opens after your attempt
Correct Answer

A. \( \frac{5}{4}\)

Step 1

Concept

\( \sqrt{\frac{25}{16}}=\frac{5}{4}\) because the principal square root is positive. Take the root of both numerator and denominator.

Step 2

Why this answer is correct

The correct answer is A. \( \frac{5}{4}\). \( \sqrt{\frac{25}{16}}=\frac{5}{4}\) because the principal square root is positive. Take the root of both numerator and denominator.

Step 3

Exam Tip

\( \sqrt{\frac{25}{16}}=\frac{5}{4}\) क्योंकि धनात्मक वर्गमूल लिया जाता है। भिन्न के वर्गमूल में अंश और हर दोनों का मूल लें।

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Mathematics Answer, Explanation and Revision Hints

संख्या रेखा पर \( \sqrt{\frac{25}{16}} \) किस बिंदु के बराबर है? / On the number line, \( \sqrt{\frac{25}{16}} \) is equal to which point?

Correct Answer: A. \( \frac{5}{4}\). Explanation: \( \sqrt{\frac{25}{16}}=\frac{5}{4}\) क्योंकि धनात्मक वर्गमूल लिया जाता है। भिन्न के वर्गमूल में अंश और हर दोनों का मूल लें। / \( \sqrt{\frac{25}{16}}=\frac{5}{4}\) because the principal square root is positive. Take the root of both numerator and denominator.

Which concept should I revise for this Mathematics MCQ?

\( \sqrt{\frac{25}{16}}=\frac{5}{4}\) because the principal square root is positive. Take the root of both numerator and denominator.

What exam hint can help solve this Mathematics question?

\( \sqrt{\frac{25}{16}}=\frac{5}{4}\) क्योंकि धनात्मक वर्गमूल लिया जाता है। भिन्न के वर्गमूल में अंश और हर दोनों का मूल लें।