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In the proof of (\sqrt{5}), what does finding both (a) and (b) divisible by (5) show?

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Answer and explanation

Correct answer: They cannot be coprime

Step 1: If both are divisible by (5), both have (5) as a common factor. Step 2: This cannot happen for coprime numbers. Step 3: Thus the initial rational assumption becomes false.

Tags

sqrt5 proofcontradictioncoprimeclass 10

Frequently asked questions

What is the correct answer to this question?

They cannot be coprime

Why is this the correct answer?

Step 1: If both are divisible by (5), both have (5) as a common factor. Step 2: This cannot happen for coprime numbers. Step 3: Thus the initial rational assumption becomes false.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Proof of irrationality of √2, √3, √5.

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