एक समान्तर श्रेणी में \(a_{14}=92\) और \(a_{38}=284\) है। \(a_{26}\) क्या होगा?

In an AP, \(a_{14}=92\) and \(a_{38}=284\). What is \(a_{26}\)?

Explanation opens after your attempt
Correct Answer

B. (188)

Step 1

Concept

\(a_{26}\) is equally spaced between \(a_{14}\) and \(a_{38}\). Therefore \(a_{26}=\frac{92+284}{2}=188\).

Step 2

Why this answer is correct

The correct answer is B. (188). \(a_{26}\) is equally spaced between \(a_{14}\) and \(a_{38}\). Therefore \(a_{26}=\frac{92+284}{2}=188\).

Step 3

Exam Tip

\(a_{26}\), \(a_{14}\) और \(a_{38}\) के बीच समान दूरी पर है। इसलिए \(a_{26}=\frac{92+284}{2}=188\)।

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Mathematics Answer, Explanation and Revision Hints

एक समान्तर श्रेणी में \(a_{14}=92\) और \(a_{38}=284\) है। \(a_{26}\) क्या होगा? / In an AP, \(a_{14}=92\) and \(a_{38}=284\). What is \(a_{26}\)?

Correct Answer: B. (188). Explanation: \(a_{26}\), \(a_{14}\) और \(a_{38}\) के बीच समान दूरी पर है। इसलिए \(a_{26}=\frac{92+284}{2}=188\)। / \(a_{26}\) is equally spaced between \(a_{14}\) and \(a_{38}\). Therefore \(a_{26}=\frac{92+284}{2}=188\).

Which concept should I revise for this Mathematics MCQ?

\(a_{26}\) is equally spaced between \(a_{14}\) and \(a_{38}\). Therefore \(a_{26}=\frac{92+284}{2}=188\).

What exam hint can help solve this Mathematics question?

\(a_{26}\), \(a_{14}\) और \(a_{38}\) के बीच समान दूरी पर है। इसलिए \(a_{26}=\frac{92+284}{2}=188\)।