If \(x\neq0\), what is the simplified form of \(\left(\frac{3x^{-2}}{x^{3}}\right)^{-2}\cdot x^{-1}\)?यदि \(x\neq0\), तो \(\left(\frac{3x^{-2}}{x^{3}}\right)^{-2}\cdot x^{-1}\) का सरल रूप क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{x^{9}}{9}\)\(\frac{x^{9}}{9}\)
Inside, \(\frac{3x^{-2}}{x^{3}}=3x^{-5}\), so \(\left(3x^{-5}\right)^{-2}\cdot x^{-1}=\frac{x^{10}}{9}\cdot x^{-1}=\frac{x^{9}}{9}\). In exams, simplify the bracket first.अंदर \(\frac{3x^{-2}}{x^{3}}=3x^{-5}\), इसलिए \(\left(3x^{-5}\right)^{-2}\cdot x^{-1}=\frac{x^{10}}{9}\cdot x^{-1}=\frac{x^{9}}{9}\)। परीक्षा में पहले कोष्ठक को सरल करें।
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