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If \(x+\frac{1}{x}=7\), what is the value of \(x^{2}+\frac{1}{x^{2}}\)?यदि \(x+\frac{1}{x}=7\), तो \(x^{2}+\frac{1}{x^{2}}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (47)(47)
We use \(\left(x+\frac{1}{x}\right)^{2}=x^{2}+\frac{1}{x^{2}}+2\). Thus \(49=x^{2}+\frac{1}{x^{2}}+2\), so the value is (47).\(\left(x+\frac{1}{x}\right)^{2}=x^{2}+\frac{1}{x^{2}}+2\) होता है। इसलिए \(49=x^{2}+\frac{1}{x^{2}}+2\) और मान (47) है।
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