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If \(x+\frac{1}{x}=5\), what is the value of \(x^{2}+\frac{1}{x^{2}}\)?यदि \(x+\frac{1}{x}=5\), तो \(x^{2}+\frac{1}{x^{2}}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (23)(23)
Since \(\left(x+\frac{1}{x}\right)^{2}=x^{2}+\frac{1}{x^{2}}+2\), we get \(25=x^{2}+\frac{1}{x^{2}}+2\). In exams, use the identity and subtract (2).\(\left(x+\frac{1}{x}\right)^{2}=x^{2}+\frac{1}{x^{2}}+2\), इसलिए \(25=x^{2}+\frac{1}{x^{2}}+2\)। परीक्षा में पहचान लगाकर (2) घटाएं।
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