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If \(x^{2}-\frac{1}{x^{2}}=60\) and \(x-\frac{1}{x}=6\), what is the value of \(x+\frac{1}{x}\)?यदि \(x^{2}-\frac{1}{x^{2}}=60\) और \(x-\frac{1}{x}=6\), तो \(x+\frac{1}{x}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (10)(10)
We use \(x^{2}-\frac{1}{x^{2}}=\left(x-\frac{1}{x}\right)\left(x+\frac{1}{x}\right)\). Thus \(60=6\left(x+\frac{1}{x}\right)\), so the value is (10).\(x^{2}-\frac{1}{x^{2}}=\left(x-\frac{1}{x}\right)\left(x+\frac{1}{x}\right)\) है। इसलिए \(60=6\left(x+\frac{1}{x}\right)\) और मान (10) है।
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