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If \(x^{2}-\frac{1}{x^{2}}=40\) and \(x-\frac{1}{x}=5\), what is the value of \(x+\frac{1}{x}\)?यदि \(x^{2}-\frac{1}{x^{2}}=40\) और \(x-\frac{1}{x}=5\), तो \(x+\frac{1}{x}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (8)(8)
We use \(x^{2}-\frac{1}{x^{2}}=\left(x-\frac{1}{x}\right)\left(x+\frac{1}{x}\right)\). Thus \(40=5\left(x+\frac{1}{x}\right)\), so the value is (8).\(x^{2}-\frac{1}{x^{2}}=\left(x-\frac{1}{x}\right)\left(x+\frac{1}{x}\right)\) है। इसलिए \(40=5\left(x+\frac{1}{x}\right)\), और मान (8) है।
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