If (2 ) and (-1 ) are zeroes of (p(x)=ax^2+bx+c ), what is the value of (\frac{b}{a} )?
Answer and explanation
Correct answer: -1
For the quadratic polynomial (p(x)=ax^2+bx+c ), the sum of the zeroes is (-\frac{b}{a} ). Here, the sum of the zeroes is (2+(-1)=1 ). Thus, (-\frac{b}{a}=1 ), so (\frac{b}{a}=-1 ). Option 1 is incorrect because it is the sum of the zeroes, not (\frac{b}{a} ). Exam tip: remember the negative sign in the relation between the sum of zeroes and (\frac{b}{a} ).
Frequently asked questions
What is the correct answer to this question?
-1
Why is this the correct answer?
For the quadratic polynomial (p(x)=ax^2+bx+c ), the sum of the zeroes is (-\frac{b}{a} ). Here, the sum of the zeroes is (2+(-1)=1 ). Thus, (-\frac{b}{a}=1 ), so (\frac{b}{a}=-1 ). Option 1 is incorrect because it is the sum of the zeroes, not (\frac{b}{a} ). Exam tip: remember the negative sign in the relation between the sum of zeroes and (\frac{b}{a} ).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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