यदि (p(x)=x-2-5x+6) के शून्यक \(\alpha,\beta\) हैं, तो (\(\alpha-\beta\)2) क्या है?
If the zeroes of (p(x)=x-2-5x+6) are \(\alpha,\beta\), what is (\(\alpha-\beta\)2)?
Explanation opens after your attempt
A. (1)
Concept
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=25-24=1). This identity avoids finding the zeroes separately.
Why this answer is correct
The correct answer is A. (1). (\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=25-24=1). This identity avoids finding the zeroes separately.
Exam Tip
(\(\alpha-\beta\)2=\(\alpha+\beta\)2-4\alpha\beta=25-24=1)। इस पहचान से शून्यक निकाले बिना उत्तर मिल जाता है।
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