यदि \(x^2-9x+20=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या होगा?
If the roots of \(x^2-9x+20=0\) are \(\alpha\) and \(\beta\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?
Explanation opens after your attempt
Correct Answer
A. \( \frac{9}{20}\)
Concept
\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{20}\). In exams, first write sum and product in reciprocal questions.
Why this answer is correct
The correct answer is A. \( \frac{9}{20}\). \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{20}\). In exams, first write sum and product in reciprocal questions.
Exam Tip
\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{20}\) होता है। परीक्षा में reciprocal वाले प्रश्न में पहले योग और गुणनफल लिखें।
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