यदि \(x^2-24x+135=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या होगा?

If the roots of \(x^2-24x+135=0\) are \(\alpha\) and \(\beta\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?

Explanation opens after your attempt
Correct Answer

A. \( \frac{8}{45}\)

Step 1

Concept

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\). In exams, write the answer in simplest form.

Step 2

Why this answer is correct

The correct answer is A. \( \frac{8}{45}\). \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\). In exams, write the answer in simplest form.

Step 3

Exam Tip

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\) होता है। परीक्षा में उत्तर को सरल रूप में लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2-24x+135=0\) के मूल \(\alpha\) और \(\beta\) हैं, तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या होगा? / If the roots of \(x^2-24x+135=0\) are \(\alpha\) and \(\beta\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?

Correct Answer: A. \( \frac{8}{45}\). Explanation: \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\) होता है। परीक्षा में उत्तर को सरल रूप में लिखें। / \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\). In exams, write the answer in simplest form.

Which concept should I revise for this Mathematics MCQ?

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\). In exams, write the answer in simplest form.

What exam hint can help solve this Mathematics question?

\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}\) होता है। परीक्षा में उत्तर को सरल रूप में लिखें।