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If the roots of (x^2-24x+135=0) are (\alpha) and (\beta), what is (\frac{1}{\alpha}+\frac{1}{\beta})?यदि (x^2-24x+135=0) के मूल (\alpha) और (\beta) हैं, तो (\frac{1}{\alpha}+\frac{1}{\beta}) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ( \frac{8}{45}) / (\frac{8}{45})( \frac{8}{45}) / (\frac{8}{45})
(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}). In exams, write the answer in simplest form.(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{24}{135}=\frac{8}{45}) होता है। परीक्षा में उत्तर को सरल रूप में लिखें।
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