यदि \(\sqrt{5}=\frac{x}{y}\) और (x,y) सहअभाज्य हैं, तो \(x^2=5y^2\) से कौन-सा निष्कर्ष तुरंत निकलता है?

If \(\sqrt{5}=\frac{x}{y}\) and (x,y) are coprime, which conclusion follows immediately from \(x^2=5y^2\)?

Explanation opens after your attempt
Correct Answer

A. \(5\mid x\)

Step 1

Concept

\(x^2=5y^2\) shows that \(x^2\) has (5) as a factor.

Step 2

Why this answer is correct

Since (5) is prime, (x) is also divisible by (5).

Step 3

Exam Tip

Conclude about (x) first, then move to (y). चरण 1: \(x^2=5y^2\) बताता है कि \(x^2\) में (5) गुणनखंड है। चरण 2: (5) अभाज्य है, इसलिए (x) भी (5) से विभाज्य होगा। चरण 3: पहले (x) पर निष्कर्ष निकालें, फिर (y) पर जाएँ।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\sqrt{5}=\frac{x}{y}\) और (x,y) सहअभाज्य हैं, तो \(x^2=5y^2\) से कौन-सा निष्कर्ष तुरंत निकलता है? / If \(\sqrt{5}=\frac{x}{y}\) and (x,y) are coprime, which conclusion follows immediately from \(x^2=5y^2\)?

Correct Answer: A. \(5\mid x\). Explanation: चरण 1: \(x^2=5y^2\) बताता है कि \(x^2\) में (5) गुणनखंड है। चरण 2: (5) अभाज्य है, इसलिए (x) भी (5) से विभाज्य होगा। चरण 3: पहले (x) पर निष्कर्ष निकालें, फिर (y) पर जाएँ। / Step 1: \(x^2=5y^2\) shows that \(x^2\) has (5) as a factor. Step 2: Since (5) is prime, (x) is also divisible by (5). Step 3: Conclude about (x) first, then move to (y).

Which concept should I revise for this Mathematics MCQ?

\(x^2=5y^2\) shows that \(x^2\) has (5) as a factor.

What exam hint can help solve this Mathematics question?

Conclude about (x) first, then move to (y). चरण 1: \(x^2=5y^2\) बताता है कि \(x^2\) में (5) गुणनखंड है। चरण 2: (5) अभाज्य है, इसलिए (x) भी (5) से विभाज्य होगा। चरण 3: पहले (x) पर निष्कर्ष निकालें, फिर (y) पर जाएँ।