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If (r) is a prime number and (\sqrt{r}=\frac{p}{q}) is assumed in lowest form, what is the first general conclusion from (p^2=rq^2)?

Answer and explanation

Correct answer: (r\mid p)

Step 1: From (p^2=rq^2), we get (r\mid p^2). Step 2: Since (r) is prime, (r\mid p). Step 3: After this, put (p=rk) to show (r\mid q).

Related tags

Real-NumbersGeneral-ProofPrime-RootDivisibilityProof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

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