If \(p(x)=x^3-2x^2+x\), what is the value of \(p(1)\)?
Answer and explanation
Correct answer: 0
To find \(p(1)\), substitute \(x=1\) in the polynomial: \(p(1)=1^3-2(1)^2+1=1-2+1=0\). Hence, the correct answer is 0. The closest distractor, 1, results from not combining the terms correctly; the term \(-2x^2\) contributes \(-2\), not \(+2\). In an exam, substitute the given value directly to check the value of a polynomial or its zero.
Frequently asked questions
What is the correct answer to this question?
0
Why is this the correct answer?
To find \(p(1)\), substitute \(x=1\) in the polynomial: \(p(1)=1^3-2(1)^2+1=1-2+1=0\). Hence, the correct answer is 0. The closest distractor, 1, results from not combining the terms correctly; the term \(-2x^2\) contributes \(-2\), not \(+2\). In an exam, substitute the given value directly to check the value of a polynomial or its zero.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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