यदि (p(x)=x-2-8x+15), तो शून्यकों के वर्गों का योग क्या है?

If (p(x)=x-2-8x+15), what is the sum of squares of its zeroes?

Explanation opens after your attempt
Correct Answer

A. (34)

Step 1

Concept

If the zeroes are \(\alpha,\beta\), then \(\alpha+\beta=8\) and \(\alpha\beta=15\). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34).

Step 2

Why this answer is correct

The correct answer is A. (34). If the zeroes are \(\alpha,\beta\), then \(\alpha+\beta=8\) and \(\alpha\beta=15\). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34).

Step 3

Exam Tip

यदि शून्यक \(\alpha,\beta\) हैं, तो \(\alpha+\beta=8\) और \(\alpha\beta=15\)। (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34)।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-8x+15), तो शून्यकों के वर्गों का योग क्या है? / If (p(x)=x-2-8x+15), what is the sum of squares of its zeroes?

Correct Answer: A. (34). Explanation: यदि शून्यक \(\alpha,\beta\) हैं, तो \(\alpha+\beta=8\) और \(\alpha\beta=15\)। (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34)। / If the zeroes are \(\alpha,\beta\), then \(\alpha+\beta=8\) and \(\alpha\beta=15\). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34).

Which concept should I revise for this Mathematics MCQ?

If the zeroes are \(\alpha,\beta\), then \(\alpha+\beta=8\) and \(\alpha\beta=15\). (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34).

What exam hint can help solve this Mathematics question?

यदि शून्यक \(\alpha,\beta\) हैं, तो \(\alpha+\beta=8\) और \(\alpha\beta=15\)। (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta=64-30=34)।