यदि (p(x)=x-2-10x+19), तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) का मान क्या है, जहाँ \(\alpha,\beta\) इसके शून्यक हैं?
If (p(x)=x-2-10x+19), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\), where \(\alpha,\beta\) are its zeroes?
Explanation opens after your attempt
Correct Answer
A. \(\frac{10}{19}\)
Concept
The sum of zeroes is (10) and the product is (19). Hence \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{10}{19}\).
Why this answer is correct
The correct answer is A. \(\frac{10}{19}\). The sum of zeroes is (10) and the product is (19). Hence \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{10}{19}\).
Exam Tip
शून्यकों का योग (10) और गुणनफल (19) है। अतः \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{10}{19}\)।
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