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If (p(x)=ax^2+bx+c) with (a\neq0) and (p(1)=p(-1)=0), what is the value of (b)?

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Answer and explanation

Correct answer: (0)

(p(1)=a+b+c) and (p(-1)=a-b+c); subtracting gives (2b=0). In exams, use addition or subtraction for symmetric inputs.

Related tags

PolynomialsOne-VariableValues

Frequently asked questions

What is the correct answer to this question?

(0)

Why is this the correct answer?

(p(1)=a+b+c) and (p(-1)=a-b+c); subtracting gives (2b=0). In exams, use addition or subtraction for symmetric inputs.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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