यदि (p(x)=2x-2-9x+4), तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या है, जहाँ \(\alpha,\beta\) शून्यक हैं?
If (p(x)=2x-2-9x+4), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\), where \(\alpha,\beta\) are zeroes?
Explanation opens after your attempt
Correct Answer
A. \(\frac{9}{4}\)
Concept
\(\alpha+\beta=\frac{9}{2}\) and \(\alpha\beta=2\). Hence \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{4}\).
Why this answer is correct
The correct answer is A. \(\frac{9}{4}\). \(\alpha+\beta=\frac{9}{2}\) and \(\alpha\beta=2\). Hence \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{4}\).
Exam Tip
\(\alpha+\beta=\frac{9}{2}\) और \(\alpha\beta=2\) हैं। इसलिए \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{4}\)।
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