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If (p(x)=2x^2-9x+4), what is (\frac{1}{\alpha}+\frac{1}{\beta}), where (\alpha,\beta) are zeroes?यदि (p(x)=2x^2-9x+4), तो (\frac{1}{\alpha}+\frac{1}{\beta}) क्या है, जहाँ (\alpha,\beta) शून्यक हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (\frac{9}{4})(\frac{9}{4})
(\alpha+\beta=\frac{9}{2}) and (\alpha\beta=2). Hence (\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{4}).(\alpha+\beta=\frac{9}{2}) और (\alpha\beta=2) हैं। इसलिए (\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}=\frac{9}{4})।
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