यदि (p(x)=2x-2-3x+\sqrt{2}), तो यह किस प्रकार का बहुपद है?

If (p(x)=2x-2-3x+\sqrt{2}), what type of polynomial is it?

Explanation opens after your attempt
Correct Answer

A. वास्तविक गुणांकों वाला द्विघात बहुपदQuadratic polynomial with real coefficients

Step 1

Concept

\(\sqrt{2}\) is real but irrational, so the coefficients are real but not all rational. Since the degree is (2), it is quadratic.

Step 2

Why this answer is correct

The correct answer is A. वास्तविक गुणांकों वाला द्विघात बहुपद / Quadratic polynomial with real coefficients. \(\sqrt{2}\) is real but irrational, so the coefficients are real but not all rational. Since the degree is (2), it is quadratic.

Step 3

Exam Tip

\(\sqrt{2}\) वास्तविक लेकिन अपरिमेय है, इसलिए गुणांक वास्तविक हैं पर सभी परिमेय नहीं। घात (2) होने से यह द्विघात है।

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Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=2x-2-3x+\sqrt{2}), तो यह किस प्रकार का बहुपद है? / If (p(x)=2x-2-3x+\sqrt{2}), what type of polynomial is it?

Correct Answer: A. वास्तविक गुणांकों वाला द्विघात बहुपद / Quadratic polynomial with real coefficients. Explanation: \(\sqrt{2}\) वास्तविक लेकिन अपरिमेय है, इसलिए गुणांक वास्तविक हैं पर सभी परिमेय नहीं। घात (2) होने से यह द्विघात है। / \(\sqrt{2}\) is real but irrational, so the coefficients are real but not all rational. Since the degree is (2), it is quadratic.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{2}\) is real but irrational, so the coefficients are real but not all rational. Since the degree is (2), it is quadratic.

What exam hint can help solve this Mathematics question?

\(\sqrt{2}\) वास्तविक लेकिन अपरिमेय है, इसलिए गुणांक वास्तविक हैं पर सभी परिमेय नहीं। घात (2) होने से यह द्विघात है।