If (\alpha) and (\beta) are zeroes of (2x^2-3x-5), what is (\frac{1}{\alpha}+\frac{1}{\beta})?यदि (2x^2-3x-5) के शून्यक (\alpha) और (\beta) हैं, तो (\frac{1}{\alpha}+\frac{1}{\beta}) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-\frac{3}{5})(-\frac{3}{5})
(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}). Here (\frac{3}{2}\div-\frac{5}{2}=-\frac{3}{5}).(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}) है। यहां (\frac{3}{2}\div-\frac{5}{2}=-\frac{3}{5})।
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