यदि \(a_{24}=7a_{9}-18\) और \(a_9=42\) है, तो \(a_{39}\) क्या होगा?

If \(a_{24}=7a_9-18\) and \(a_9=42\), what is \(a_{39}\)?

Explanation opens after your attempt
Correct Answer

C. (504)

Step 1

Concept

\(a_{24}=276\) and (15d=234), so \(d=\frac{78}{5}\). \(a_{39}=276+15\cdot\frac{78}{5}=510\).

Step 2

Why this answer is correct

The correct answer is C. (504). \(a_{24}=276\) and (15d=234), so \(d=\frac{78}{5}\). \(a_{39}=276+15\cdot\frac{78}{5}=510\).

Step 3

Exam Tip

\(a_{24}=276\) और (15d=234), इसलिए \(d=\frac{78}{5}\)। \(a_{39}=276+15\cdot\frac{78}{5}=510\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_{24}=7a_{9}-18\) और \(a_9=42\) है, तो \(a_{39}\) क्या होगा? / If \(a_{24}=7a_9-18\) and \(a_9=42\), what is \(a_{39}\)?

Correct Answer: C. (504). Explanation: \(a_{24}=276\) और (15d=234), इसलिए \(d=\frac{78}{5}\)। \(a_{39}=276+15\cdot\frac{78}{5}=510\)। / \(a_{24}=276\) and (15d=234), so \(d=\frac{78}{5}\). \(a_{39}=276+15\cdot\frac{78}{5}=510\).

Which concept should I revise for this Mathematics MCQ?

\(a_{24}=276\) and (15d=234), so \(d=\frac{78}{5}\). \(a_{39}=276+15\cdot\frac{78}{5}=510\).

What exam hint can help solve this Mathematics question?

\(a_{24}=276\) और (15d=234), इसलिए \(d=\frac{78}{5}\)। \(a_{39}=276+15\cdot\frac{78}{5}=510\)।