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If \(a=2+\sqrt{3}\), what is the value of \(a^{2}+\frac{1}{a^{2}}\)?यदि \(a=2+\sqrt{3}\), तो \(a^{2}+\frac{1}{a^{2}}\) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (14)(14)
Here \(\frac{1}{a}=2-\sqrt{3}\), so \(a+\frac{1}{a}=4\) and \(a^{2}+\frac{1}{a^{2}}=4^{2}-2=14\). In exams, use the identity \(\left(a+\frac{1}{a}\right)^{2}\).\(\frac{1}{a}=2-\sqrt{3}\), इसलिए \(a+\frac{1}{a}=4\) और \(a^{2}+\frac{1}{a^{2}}=4^{2}-2=14\)। परीक्षा में \(\left(a+\frac{1}{a}\right)^{2}\) पहचान लगाएं।
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