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If (a^2=5) and (a>0), what is the value of (a^{-2}+a^2)?यदि (a^2=5) और (a>0), तो (a^{-2}+a^2) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (,\dfrac{26}{5},)(,\dfrac{26}{5},)
Because (a^{-2}=\dfrac{1}{a^2}=\dfrac{1}{5}), (\dfrac{1}{5}+5=\dfrac{26}{5}). In exams, write (a^{-2}) as (\dfrac{1}{a^2}).क्योंकि (a^{-2}=\dfrac{1}{a^2}=\dfrac{1}{5}), इसलिए (\dfrac{1}{5}+5=\dfrac{26}{5})। परीक्षा में (a^{-2}) को (\dfrac{1}{a^2}) लिखें।
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