यदि (6x+2y=28) और (3x+y=14), तो हलों की संख्या क्या है?

If (6x+2y=28) and (3x+y=14), what is the number of solutions?

Explanation opens after your attempt
Correct Answer

D. अनंत हलInfinitely many solutions

Step 1

Concept

The first equation is (2) times the second. Therefore both equations are identical and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is D. अनंत हल / Infinitely many solutions. The first equation is (2) times the second. Therefore both equations are identical and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (2) गुना है। इसलिए दोनों समीकरण समान हैं और अनंत हल देते हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि (6x+2y=28) और (3x+y=14), तो हलों की संख्या क्या है? / If (6x+2y=28) and (3x+y=14), what is the number of solutions?

Correct Answer: D. अनंत हल / Infinitely many solutions. Explanation: पहला समीकरण दूसरे का (2) गुना है। इसलिए दोनों समीकरण समान हैं और अनंत हल देते हैं। / The first equation is (2) times the second. Therefore both equations are identical and give infinitely many solutions.

Which concept should I revise for this Mathematics MCQ?

The first equation is (2) times the second. Therefore both equations are identical and give infinitely many solutions.

What exam hint can help solve this Mathematics question?

पहला समीकरण दूसरे का (2) गुना है। इसलिए दोनों समीकरण समान हैं और अनंत हल देते हैं।