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Three chairs and two tables cost ₹4900. Two chairs and three tables cost ₹5600. What is the price of one table?

Answer and explanation

Correct answer: ₹1400

This is a pair of linear equations solved by elimination. Let c be the price of one chair and t be the price of one table. The statements give 3c + 2t = 4900 and 2c + 3t = 5600. Multiply the first equation by 2 and the second by 3: 6c + 4t = 9800 and 6c + 9t = 16800. Subtracting eliminates c and gives 5t = 7000, so t = 1400. Therefore one table costs ₹1400, making option C correct. Substitution gives c = 700; then 3(700)+2(1400)=4900 and 2(700)+3(1400)=5600, confirming the result. The other options do not satisfy both original totals.

Related tags

Simultaneous-EquationsElimination-MethodWord-ProblemLinear-EquationsAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two VariablesMathematics

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