If the equations 4x + ky = 34 and 4x − 2y = 10 have a solution with y = 3, what is the value of k?यदि समीकरण 4x + ky = 34 और 4x − 2y = 10 का एक हल y = 3 है, तो k का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 66
Using y = 3 in 4x − 2y = 10 gives 4x − 6 = 10, so x = 4. Substituting x = 4 and y = 3 into the first equation gives 16 + 3k = 34, hence k = 6.4x − 2y = 10 में y = 3 रखने पर 4x − 6 = 10, इसलिए x = 4। अब पहले समीकरण में x = 4 और y = 3 रखने पर 16 + 3k = 34, अतः k = 6।
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