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The sum of the prices of two tickets is (180) rupees. The costlier ticket is (40) rupees more than the cheaper ticket. What is the price of the costlier ticket?

Answer and explanation

Correct answer: 110 rupees

Let the costlier ticket cost x rupees and the cheaper ticket cost y rupees. The equations are x+y=180 and x-y=40. Adding them eliminates y and gives 2x=220, so x=110 rupees. Therefore, option C is correct. In option B, the two prices would differ by 30 rupees, while in option D they would differ by 60 rupees; neither satisfies the condition. Exam tip: When the sum and difference are known, the larger quantity is (sum + difference) / 2.

Related tags

Pair Of Linear EquationsSubstitution MethodElimination MethodWord ProblemsAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two VariablesMathematics

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