The perimeter of a rectangle is (112) cm and its length is (16) cm more than its breadth. What is the area of the rectangle?

Correct answer: \(720\ \text{cm}^2\)

Let the length be \(l\) cm and the breadth be \(b\) cm. From the perimeter, \(2(l+b)=112\), so \(l+b=56\). Also, \(l-b=16\). Adding the two equations gives \(2l=72\), hence \(l=36\) and \(b=20\). Therefore, the area is \(l\times b=36\times20=720\ \text{cm}^2\). A choice such as \(700\ \text{cm}^2\) is not the product of the correct length and breadth. Exam tip: In rectangle-perimeter questions, first convert \(2(l+b)\) carefully into \(l+b\).