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A pen costs p and a notebook costs q. If 3p + 4q = 260 and 5p + 2q = 300, what is q?

Answer and explanation

Correct answer: 200/7

The price relationships form a pair of simultaneous linear equations, which can be solved by elimination. To eliminate q, multiply 5p + 2q = 300 by 2, obtaining 10p + 4q = 600. Subtract 3p + 4q = 260 from this equation: 7p = 340, so p = 340/7. Substitute into 5p + 2q = 300: 5(340/7) + 2q = 300. Since 300 = 2100/7, we get 1700/7 + 2q = 2100/7, hence 2q = 400/7 and q = 200/7. Thus option C is correct. The corresponding p and q satisfy both original price equations; the other proposed q-values do not.

Related tags

Pair Of Linear EquationsWord ProblemElimination MethodPricesAlgebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two VariablesMathematics

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