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The sum of a father’s and son’s ages is (56) years. Six years ago, the father’s age was (3) times the son’s age. What is the father’s present age?

Answer and explanation

Correct answer: (45) years

Let the present ages of the father and son be \(x\) and \(y\) years, respectively. Then \(x+y=56\). Six years ago, \(x-6=3(y-6)\), which gives \(x=3y-12\). Substituting this in the first equation, \(3y-12+y=56\), so \(4y=68\), \(y=17\), and \(x=39\). Therefore, the father’s present age is (39) years.

Related tags

Linear EquationsAge Word ProblemSubstitution MethodElimination MethodClass 10Algebraic Methods: Substitution Method And Elimination Method.Algebraic Methods Substitution Method And Elimination MethodPair Of Linear Equations In Two Variables

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